This video discusses the reaction mechanism for the formation of benzoin using sodium cyanide and benzaldehyde. The cyanide ion attacks the carbonyl carbon atom forming a tetrahedral intermediate converting the aldehyde hydrogen into an acidic hydrogen whose conjugate base is resonance stabilized by the nitrile functional group. Deprotonation of the acidic hydrogen creates a carbanion nucleophilic intermediate which can react with the electrophilic carbonyl group of the other benzaldehyde molecule thus leading to the formation of benzoin.
This video discusses the reaction mechanism for the formation of benzoin using sodium cyanide and benzaldehyde. The cyanide ion attacks the carbonyl carbon atom forming a tetrahedral intermediate converting the aldehyde hydrogen into an acidic hydrogen whose conjugate base is resonance stabilized by the nitrile functional group. Deprotonation of the acidic hydrogen creates a carbanion nucleophilic intermediate which can react with the electrophilic carbonyl group of the other benzaldehyde molecule thus leading to the formation of benzoin.
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